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Dec 21, 2020 · * Dynamically allocates a std::string array. * Asks the user to enter each name. * Calls std::sort to sort the names (See 9.4 -- Sorting an array using selection sort and 9.11 -- Pointer arithmetic and array indexing) * Prints the sorted list of names. std::string supports comparing strings via the comparison operators < and >. You don’t need ...

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C program to find the second Largest number among Three user input Numbers.2lf restricts the number till 2 decimal places. Below is a program to find the second largest number out of the three user input numbers using nested if-else loops:

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Here is an interesting program to check whether a person is eligible to vote or not. This can be easily done using an If-else condition and checking whether the age of that person is greater than or equal to the minimum allowed age for voting (18 years).

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For example, you can check whether one number is divisible by another—if x % y is zero, then x is divisible by y. Also, you can extract the right-most digit or digits from a number. For example, x % 10 yields the right-most digit of x (in base 10). For example, for the number 8, the smallest particle is 2, and the number 8 in the loop is given as 2 * 4, so i = 2, j = 4. In the starting sequence D [8] = 8, D [2] = 2 and after testing conditions if (D [2] <D [2 * 4]) ... the new value D [8] = 2, and the smallest is its divisor. Now that we know all the smallest dividers, factoring can be done:

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The smallest number that is divisible by all the numbers between 1 and 10 (given by Project Euler) is 2520. Thus, the number in question must be a multiple of 2520. (As I'm writing this, I'm starting to question whether or not this is a necessary truth, but the program does work.

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In Java, you add numbers with the "+" operator. For example, if you want to add "a" and "b", and copy the result to variable "c", the command would be: c = a + b;

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